154k views
2 votes
Find the focus for y=x^2+4x-7

1 Answer

3 votes

ANSWER


(2,-10.75)

Step-by-step explanation

The given function is


y = {x}^(2) - 4x - 7

We rewrite this function to obtain,


(y + 11) = {( x- 2)}^(2)

We now compare this function to


(y - k) = 4p {( x- h)}^(2)

We have


4p = 1

This implies that,


p = (1)/(4)

The vertex is (2,-11).

The focus is


(2,-11+ (1)/(4) )


(2,- (43)/(4) )


(2,-10.75)

User Sharpmachine
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories