The change in the velocity = 4 m/s
Acceleration = 4 m/s²
Further explanation
Given
vo = initial velocity = 4 m/s
vf = final velocity = 8 m/s
t = 1 s
Required
The change in the velocity
Acceleration
Solution
the change in velocity =
![\tt vf-vo=8-4=4~m/s](https://img.qammunity.org/2022/formulas/chemistry/college/x03smu2b77cbq9nxad4fifko6aoddnwjvy.png)
Acceleration = ratio of a change in velocity and the time
![\tt a=(\Delta v)/(t)= (vf-vo)/(t)](https://img.qammunity.org/2022/formulas/chemistry/college/lsq6m1xqtxsge1uvefsqcsir10okxew5pw.png)
Input the value :
![\tt a=(4~m/s)/(1~s)=4~m/s^2](https://img.qammunity.org/2022/formulas/chemistry/college/lvvdjwf1si8lgz20zi0rowxmhluwa46tww.png)