Question

Write the equation of a line perpendicular to the given line and passing through the given point. y=3x+3(-1,-1) step by step

Answer 1

`y = - (1)/(3) x -(4)/(3)`

Step-by-step explanation

The given line is

`y = 3x + 3`

The given point is

`(-1,-1)`

The slope of the given line is

`m = 3`

We found this by comparing

`y = 3x + 3`

to

`y = mx + b`

If two lines are perpendicular, then one is the negative reciprocal of the other.

Hence the slope of the required line is

`- (1)/(3)`

Using the point-slope formula or otherwise, we can find the required equation.

`y-y_1=m(x-x_1)`

We substitute the slope and point to get:

`y + 1 = - (1)/(3) (x + 1)`

`y = - (1)/(3) x -(4)/(3)`