Question

y=3x+3;(-1,-1) write the equation of a line parallel to the given line and passing through the given point

Answer 1

The desired equation is y = 3x + 2

Explanation:

A NEW LINE parallel to y = 3x + 3 has an equation that is identical to y = 3x + 3 except that the y-intercept will be different.

Start with y = 3x + 3; replace x with -1 and y with -1 (which come from the given point): -1 = 3(-1) + b. Then -1 = -3 + b, and b must be +2.

The desired equation is y = 3x + 2.