Question

Need Help Please, This One Is A Bit Difficult.

Answer 1

Area of given figure = 432 unit ²

Explanation:

Points to remember

Area of trapezoid = h(a + b)/2

Where h - height and a and b are two parallel sides

To find the area of given figure

It is given two trapezoid

Area of 1st trapezoid

h = 16, a = 25 and b = 4

Area = h(a+ b)/2

= 16(25 + 4)/2

= 232 units ²

Area of 2nd trapezoid

h = 10, a = 25 and b = 15

Area = h(a+ b)/2

= 10(25 + 15)/2

= 200 units ²

Total area = 232 + 200 = 432 units²

Answer 2

Answer: 432 units²

Explanation:

The figure is composed by two trapezoids.

The formula for calculate the area of a trapezoid is:

`A=(h)/(2)(B+b)`

Where "B" is the larger base, "b" is the smaller base and "h" is the height.

Let be
`A_f` the area of the figure,
`A_1` the area of the trapezoid on the left and
`A_2` the area of the trapezoid of the right. Then the area of the figure will be:

`A_f=A_1+A_2`

`A_f=(h_1)/(2)(B_1+b_1)+(h_2)/(2)(B_2+b_2)`

Substituting values, you get:

`A_f=(16units)/(2)(25units+4units)+(10units)/(2)(25units+15units)=432units^2`