Question

A fish is swimming at 500 KM/hour and suddenly as shark appears behind, for 5 seconds the fish is swimming in the same direction but increases its speed to 2500 Km/H What is its average acceleration?

Answer 1

`a =111.1\ m/s^2`

Explanation:

The formula to calculate the average acceleration is:

`a =(s_2-s_1)/(t_2-t_1)`

Where s is the speed of the object and t is the time it takes the object to change its speed
`s_1` to the speed
`s_2`

In this case we have that:

`t_2-t_1 = 5\ sec`

`s_1 = 500\ km/h = 500*(1\ h)/(3600\ s)*(1000\ m)/(1\ km)=138.89\ m/s`

`s_2= 2500\ km/h = 2500*(1\ h)/(3600\ s)*(1000\ m)/(1\ km)=694.44\ m/s`

`a =(694.44-138.89)/(5)\ m/s^2`

`a =111.1\ m/s^2`