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If angle PQR and angle RQS form a linear pair and angle PQR =5x+5 and angle RQS =11x-65 then angle PQR=?

User Errakeshpd
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1 Answer

4 votes

Answer:

m<PQR = 80°

Explanation:

Points to remember

Sum angles in a linear pair is 180

To find the value of x

It is given that, angle PQR and angle RQS are linear pairs, and

m< PQR =5x+5 and m<RQS =11x-65

m<PQR + m<RQS = 180

5x + 5 + 11x - 65 = 180

16x -60 = 180

16x = 180 + 60

16x = 240

x = 15

To find the value of angle PQR

m<PQR = 5x + 5

= 5*15 + 5

= 75 + 5 = 80

Therefore m<PQR = 80°

User LordMarty
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