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A parallelogram has vertices (5, 0), (3, -3), (-4, -3), and (-2, 0). What is the approximate perimeter of the parallelogram?

User Flo Bayer
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2 Answers

2 votes

Answer:

C: 30 units

Explanation:

on edge 2021! hope this helps!!~ d=(´▽`)=b

User SnazzyBootMan
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2 votes

Check the picture below.

so the top and bottom segments are simply 7 units, we can read that off the grid. Let's find the length of the other two segments, "c".


\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=√(a^2+b^2) \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{2}\\ b=\stackrel{opposite}{3}\\ \end{cases} \\\\\\ c=√(2^2+3^2)\implies c=√(13) \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{perimeter of the parallelogram}}{7+7+√(13)+√(13)}\qquad \approx \qquad 21.21

A parallelogram has vertices (5, 0), (3, -3), (-4, -3), and (-2, 0). What is the approximate-example-1
User Bastes
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