Question

Line segment AB has endpoints A(1,-3) and B(-2,1). What is the midpoint of line segment AB

Answer 1

`\large\boxed{\left(-(1)/(2),\ -1\right)}`

Explanation:

`\text{The formula of a midpoint:}\\\\\left((x_1+x_2)/(2);\ (y_1+y_2)/(2)\right)\\\\================================\\\\A(1,\ -3),\ B(-2,\ 1)\\\\\text{Substitute:}\\\\x=(1+(-2))/(2)=(-1)/(2)=-(1)/(2)\\\\y=(-3+1)/(2)=(-2)/(2)=-1`

Answer 2

`((-1)/(2) ,-1)`

Explanation:

line segment AB has endpoints A(1,-3) and B(-2,1).

To find the midpoint of AB we use formula

`((x_1+x_2)/(2) ,(y_1+y_2)/(2) )`

A(1,-3) is (x1,y1) , B(-2,1) is (x2,y2)

Plug in the values in the formula

`((1-2)/(2) ,(-3+1)/(2) )`

`((-1)/(2) ,(-2)/(2) )`

`((-1)/(2) ,-1)`