Question

Perform the indicated operation.
(w^3 +64)/(4+ w)

Answer 1

(w^2 - 4w + 16)

Explanation:

Note that w^3 +64 is the sum of two perfect cubes, which are (w)^3 and (4)^3. The corresponding factors are (w + 4)(w^2 - 4w + 16).

Therefore,

(w^3 +64)/(4+ w) reduces as follows:

(w^3 +64)/(4+ w) (4 + w)(w^2 - 4w + 16)

--------------------------- = --------------------------------- = (w^2 - 4w + 16)

4 + w 4 + w