Question

I need help with this Algebra problem please!!!!!!

Answer 1

Answer: D

Explanation:

Switch the x and y values:

`f(x)=2^x+6`

`y=2^x+6`

`x=2^y+6`

Now we have to solve for the y value. Subtract 6 on both sides:

`x-6=2^y`

If we take the log of both sides, with a base of 2, the right hand side will be explicitly solved for y:

`log_2(x-6)=log_2(2^y)=y`