Question

Which is the axis of symmetry of a parabola with equation x^2=-4y?

Answer 1

x = 0

Explanation:

Given

x² = - 4y ( divide both sides by - 4 )

y = -
`(1)/(4)` x²

Which is a parabola opening vertically down with it's vertex at (0, 0) and symmetrical about the y- axis

Hence equation of axis of symmetry is x = 0