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An object is dropped from a small plane. As the object falls, its distance, d, above the ground after t seconds, is given by the

formula d = -162 + 1,000. Which inequality can be used to find the interval of time taken by the object to reach the height
greater than 300 feet above the ground?
O -166 +1,000 < 300
0 -1672 +1,000 3 300
O-166 +1,000 300
O -166 +1,000 > 300
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User Celebi
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1 Answer

1 vote

Answer:


-16t^2 + 1,000>300


t<6.61\ s

Explanation:

We know that the distance of the object while falling is given by the equation:


d = -16t^2 + 1,000

To find the time interval in which the object is at a height greater than 300 ft, we must do


d> 300

So


-16t^2 + 1,000>300


-16t^2>-700


16t^2<700


t^2<(700)/(16)


t<\sqrt{(700)/(16)}


t<6.61\ s

The interval is

t ∈ (0, 6.61)

And the inequality used is:
-16t^2 + 1,000>300

User JonathanTien
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7.0k points
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