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What is the area (in square units) of the region under the curve of the function f(x)=x+3, on the interval from x=1 to x=3 ?

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5 votes

Answer:

10 square units

Explanation:

We want to find the area under the curve
f(x)=x+3 from x=1 to x=3.

We use definite integrals to find this area.


\int\limits^3_1 {x+3} \, dx

We integrate to obtain:


(x^2)/(2)+3x|_1^3

We evaluate the limits to get:


(3^2)/(2)+3(3)-((1^2)/(2)+3(1))


4.5+9-0.5-3=10

Therefore the area under the curve from x=1 to x=3 is 10 square unit.

User Goodfellow
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