Question

Write the equation of the parabola with a vertex at (-3,-10) and y-intercept of (0,-1)

Answer 1

y = (x+ 3)^2 - 10.

Explanation:

Vertex form is

y = a(x - b)^2 + c

Here b = -3 and c = -10 so we have

y = a(x + 3)^2 - 10 where a is some constant.

The y intercept is (0, -1) so substituting:

-1 = a * 3^2 - 10

-1 + 10 = 9a

9a = 9

a = 1

So the required parabola is (x+ 3)^2 - 10.