Question

A surveyor starts at the southeast corner of a lot and

charts the following displacements: A = 600 m, N;
B = 400 m, W; C = 200 m, S; and D = 100 m, E.
What is the net displacement from the starting point?​

Answer 1

Find the difference vertically( North and South) and the difference horizontally ( East and West)

Then use the Pythagorean Theorem.

600 North - 200 South = 400 m

400 West - 100 East = 300 m

Now using the Pythagorean Theorem;

400^2 + 300^2 = total displacement^2

Total displacement^2 = 160,000 + 90,000

Total displacement^2 = 250,000

Total displacement = √250,000

Total displacement = 500 m