Answer:

Explanation:
step 1
Find the scale factor
we know that
If two figures are similar, then the ratio of its perimeters is equal to the scale factor
Let
z ----> the scale factor
x----> the perimeter of the larger figure
y ----> the perimeter of the smaller figure

we have


substitute

step 2
Find the area of the larger figure
we know that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
Let
z ----> the scale factor
x----> the area of the larger figure
y ----> the area of the smaller figure

we have


substitute

