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Jimmy is trying to dive down and touch the bottom of the pool. On his first try he makes it 1/3 of the way to the bottom. On his second try he makes it 3/5 of the way to the bottom. Jimmys second dive was deeper than his first dive by what fraction of the pool?

User CCCC
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1 Answer

4 votes

Answer:

Jimmy's second dive was
(4)/(15) of the pool deeper than the first one

Step-by-step explanation:

We are given that:

First dive was
(1)/(3) of the way to the bottom

Second dive was
(3)/(5) of the way to the bottom

We know that the second dive was deeper than the first one since
(3)/(5) > (1)/(3)

To know how much deeper the second dive was compared to the first one, we will simply subtract the depth of the first dive from that of the second one

Therefore:

The second dive was
(3)/(5) - (1)/(3) = (9)/(15) - (5)/(15) = (4)/(15) of the pool deeper than the first one

Hope this helps :)

User Mirushaki
by
6.0k points
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