Question

Lf f(x) = 5x, what is f^-1(x)?

Answer 1

Answer:
`f^(-1)(x)=(x)/(5)`

Explanation:

By definition the domain of an inverse function
`f^-1(x)` is the range of f(x) and the range of the inverse function is equal to the domain of the principal function f(x).

If you have a function
`f(x)=5x`, then to find the inverse function, follow these steps:

1. Make
`y=f(x)`

`f(x)=y=5x`

`y=5x`

2. Solve for the variable "x":

`x=(y)/(5)`

3. Exchange the variable "x" with the variable "y":

`y=(x)/(5)`

4. Exchange "y" with
`f^(-1)(x)`. Then the inverse function is:

`f^(-1)(x)=(x)/(5)`