Answer: Third Option
![y = -10x + 110](https://img.qammunity.org/2020/formulas/mathematics/high-school/ko18097b22rj4hozmi9n679xudgbqjw39w.png)
Explanation:
The equation of a line in the pending intersection form has the following form:
![y=mx +b](https://img.qammunity.org/2020/formulas/mathematics/high-school/1s2kbefr9gjvi02432qs1z0zvaage6cn0f.png)
Where m is the slope of the line and b is the intersection with the y axis.
Observe in the graph that the data form a decreasing line. Then the adjustment line must have a negative slope
.
The first and the second option have positive slopes, therefore we discard them.
Notice in the scatter diagram that the intersection of the line with the y-axis (x = 0) is above 90.
The line of the fourth option has a value of
.
Therefore the line that best fits the data is the third option
![y = -10x + 110](https://img.qammunity.org/2020/formulas/mathematics/high-school/ko18097b22rj4hozmi9n679xudgbqjw39w.png)
Note that the line has a slope
and a value of
![b> 90](https://img.qammunity.org/2020/formulas/mathematics/high-school/o1e8aysu3m660r1kdgm110i533r74htw6k.png)