Question

When 24g of magnesium metal is heated in air, 40g of magnesium oxide is produced. What mass of magnesium would be needed in order to produce 10g of magnesium oxide?

Answer 1

To produce 10g of magnesium oxide, 6g of magnesium would be needed.

Step-by-step explanation:

To find the mass of magnesium needed to produce 10g of magnesium oxide, we can use the given information about the reaction between magnesium and oxygen. From the given information, we know that when 24g of magnesium is heated in air, 40g of magnesium oxide is produced. This means that the reaction produces a 1:1 ratio between the mass of magnesium and the mass of magnesium oxide. Therefore, if 24g of magnesium produces 40g of magnesium oxide, then 10g of magnesium oxide would require (10g/40g) * 24g = 6g of magnesium.

Answer 2

Answer: 6.1 g

Step-by-step explanation:

between Mg and MgO theres a 1;1 MOLE RATIO

here's the balanced equation

2Mg + O2 ==> 2MgO

24g of magnesium is approximately 1 mole of magnesium so it produces 40 g of mgo which is also 1 mole of mgo thus 10/40 =0.25 moles of MgO so 0.25 moles of magnesium would be needed which is approximately 6.1 g