Question

Which polynomial function f(x) has a leading coefficient of 1, roots –4, 2, and 9 with multiplicity 1, and root –5 with multiplicity 3?

Answer 1

b: f(x) = –x2 + 8x – 16

Explanation:

I got it right in edg.

Answer 2

f(x) = (x + 5)(x + 5)(x + 5)(x + 4)(x - 2)(x - 9)

Explanation:

The polynomial function f(x) possessing a key coefficient of 1:

`(x+4)(x-2)(x-9)(x+5)^(3)` = 0

By opening the above equation;

f(x) = (x + 5)(x + 5)(x + 5)(x + 4)(x - 2)(x - 9)

∵ Thus, the above polynomial function makes the coefficient 1 with a multiplicity of 3 for root - 5 and 1 for -4, 2, and 9.