Question

Two red and two blocks are placed into a bag you take one of the blocks out of the bag what is the probability the block is not blue

Answer 1

the answer would be 1/2 .,

Answer 2

Question:

Two red and two blue blocks....

Answer:

`P(Not\ Blue) = (1)/(2)`

Explanation:

Given

`Red = 2`

`Blue = 2`

Required

Probability of not selecting blue

First, we calculate the probability of selecting blue

`P(Blue) = (Blue)/(Total)`

`P(Blue) = (2)/(2+2)`

`P(Blue) = (2)/(4)`

`P(Blue) = (1)/(2)`

In probability:

Opposite probabilities sum up to 1 i.e.

`P(Blue) + P(Not\ Blue) = 1`

This gives

`(1)/(2) + P(Not\ Blue) = 1`

`P(Not\ Blue) = 1 - (1)/(2)`

`P(Not\ Blue) = (2-1)/(2)`

`P(Not\ Blue) = (1)/(2)`