Question

Factor the polynomial.

2y2 – 14y + 20
A.(y + 2)(y + 5)
B.2ly - 2)(y + 5)
C.(y-2)(x - 5)
D.2(y-2)(y-5)

Answer 1

D

Explanation:

Given

2y² - 14y + 20 ← factor out 2 from each term

= 2(y² - 7y + 10)

To factor the quadratic

Consider the factors of the constant term (+ 10) which sum to give the coefficient of the y- term (- 7)

The factors are - 2 and - 5, since

- 2 × - 5 = 10 and - 2 - 5 = - 7, so

y² - 7y + 10 = (y - 2)(y - 5) and

2y² - 14y + 20 = 2(y - 2)(y - 5) → D

Answer 2

2y^2- 14y+ 20

By splitting the middle term:

2y^2 -10y -4y +20

By taking the common outside:

2y(y-5) -4(y-5)

=(2y-4)(y-5)

=2(y-2)(y-5)

Therefore D is the right answer