Answer:
q(molar) = 1.13 Kj/mole
Step-by-step explanation:
q(specific) = (mcΔT)soln = (146g)(1cal/g°C)(24.7°C - 21.0°C)/2moles(X) = 540.2 cals/2moles(X) = 270.1 cal/mole x 4.184 j/cal = 1130 j/mol = 1.13 Kj/mol
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