Answer:
No. When the distance is doubled, the gravitational force is 1/4 times as strong, therefore, the correct answer is she is not correct
Step-by-step explanation:
The gravitational force is given as follows;

Where;
m₁, and m₂ are the masses sharing the gravitational field
G = The universal gravitational constant
r = The distance between the centers of the two masses
Therefore, when the new distance, R = 2 × r, we get;

Therefore, when the distance is doubled, the gravitational force is one fourth as strong, therefore, she is not correct.