Answer:

Explanation:
The value of a function will be zero if the factor is put in it. In order to check whether a factor is of a function or not we will put the value of x from that factor in the function:
So
x-2 = 0 => x=2
Putting in first function

So x-2 is not a factor of first function.
Putting in second function

So x-2 is also not a factor of second function.
Putting in third function:

So x-2 is factor of third function.
...........................
For x+3
x+3=0
x=-3
First function:

So x+3 is a factor of first function.
.............................
For x+4
x+4=0
x=-4
As we have already found the factors of first and third function, we will now only check second and fourth function.

So x+4 is not a factor of second function.
Putting in fourth function:

So x+4 is a factor of fourth function
..........................
For x+5=0
x=-5
Since only one function is remaining we'll only check for that.
