Question

1. m’+9 = 58

m
=
2. 7e² = 28
er
d=
3. d? + 6 = 70
4 n - 10 = 62
N=​

Answer 1

For this case we must solve each of the equations proposed:

A)
`m ^ 2 + 9 = 58`

Subtracting 9 from both sides of the equation we have:

`m ^ 2 = 49`

Applying root to both sides of the equation:

`m = \sqrt {49}\\m = \pm7`

B)
`7e ^ 2 = 28`

We divide between 7 on both sides of the equation:

`e ^ 2 = \frac {28} {7}\\e ^ 2 = 4`

We apply root to both sides of the equation:

`e = \pm \sqrt {4}\\e = \pm2`

C)
`d ^ 2 + 6 = 70`

Subtracting 6 on both sides of the equation:

`d ^ 2 = 64`

We apply root to both sides of the equation:

`d =\pm \sqrt {64}\\d = \pm8`

D)
`\frac {1} {2} n ^ 2-10 = 62`

We add 10 to both sides of the equation:

`\frac {1} {2} n ^ 2 = 72`

We multiply by 2 both sides of the equation:

`n ^ 2 = 144`

We apply root to both sides of the equation:

`n = \pm \sqrt {144}\\n =\pm12`

Answer:

`m = \pm7\\e = \pm2\\d = \pm8\\n = \pm12`