Hello!
The answers are:
- The quantity that represents the initial number of bacteria is 64.
- The quantity that represents the rate at which the number of bacteria is increasing is (1+0.12) or 1.12 which means the growth rate percentage for the bacteria is 0.12 or (0.12*100), it will be 12%.
Why?
To solve the problem, and complete the statements, we need to remember the form of the exponential growth.
The exponential growth formula is given by the following formula:
![P(t)=StartAmount(1+PercentageRate)^(t)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jams26hfsbmtsnh7zziqf4a4e33xh3s8rh.png)
Where,
Start Amount, is the starting population or amount.
(1+Percentage Rate), is the increasing rate
Percentage Rate, is the growth rate percentage.
t, is the time elapsed.
Now, we are given the following expression:
![P(3)=64(1.12)^(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rpi471wem2cdch8j68eyadvcwjakvawe23.png)
Which can be rewrited as:
![P(3)=64(1+0.12)^(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/r31a2vhq0053jv5v3hphk1mjmml1h38aiq.png)
So, we have that:
- The quantity that represents the initial number of bacteria is 64.
- The quantity that represents the rate at which the number of bacteria is increasing is (1+0.12) or 1.12 which means the growth rate percentage for the bacteria is 0.12 or (0.12*100), it will be 12%.
Have a nice day!