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If y varies inversely with x, and the constant of variation

is 4.5, what are the values missing in the table?

If y varies inversely with x, and the constant of variation is 4.5, what are the values-example-1
User Melek
by
5.8k points

2 Answers

5 votes

Answer:


A=0.5


B=4.5


C=1.5


D=0.5

Step-by-step explanation:

The form an the equation of inverse variation is:


y=(k)/(x)

Being "k" the constant of variation.

Since we know "k" and we have the values given in the table, we can find the missing values:

To find A we need to substitute the
y=9, the value of "k" and
x=A into the equation and solve for "A":


9=(4.5)/(A)


A=(4.5)/(9)=0.5

To find B we need to substitute the
x=1, the value of "k" and
y=B into the equation:


B=(4.5)/(1)=4.5

To find C we need to substitute the
y=3, the value of "k" and
x=C into the equation and solve for "C":


3=(4.5)/(C)


C=(4.5)/(3)=1.5

To find D we need to substitute the
x=9, the value of "k" and
y=D into the equation:


D=(4.5)/(9)=0.5

User Nadir Sidi
by
5.6k points
2 votes

Answer:

A. 0.5

B. 4.5

C. 1.5

D. 0.5

Explanation:

y varies inversely with x can be written as:

y = k/x

where k is constant of variation.

1. value of A

x=A, y = 9 and k = 4.5 (given)

y = k/x

9 = 4.5/A

=> A = 4.5/9

=> A=0.5

2. Value of B

x =1, y= B, k = 4.5

y = k/x

B = 4.5/1

B= 4.5

3. Value of C

x=C, y=3. k=4.5

y = k/x

3 = 4.5/C

3C = 4.5

C = 4.5/3

C = 1.5

4. Value of D

x= 9, y=D, k=4.5

y = k/x

D = 4.5/9

D = 0.5

User Aparan
by
5.2k points