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Simplify -14x^3/x^3- 5x^4 where x=?

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Explanation:


(-14x^3)/(x^3-5x^4)\qquad\text{where}\ x^3-5x^4\\eq0\\\\x^3-5x^4\\eq0\qquad\text{distributive}\\\\x^3(1-5x)\\eq0\iff x^3\\eq0\ \wedge\ 1-5x\\eq0\\\\x\\eq0\ \wedge\ x\\eq(1)/(5)\\\\(-14x^3)/(x^3(1-5x))\qquad\text{cancel}\ x^3\\\\=(-14)/(1-5x)\qquad\text{where}\ x\\eq(1)/(5)

User Sergio Flores
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