Question

I need help with this if anyone can help

Answer 1

Answer: 2-i

Explanation:

First, we can substitute i for x. Whenever there is x in the equation, we will put i. Now, we have
`f(i)=i^3-2i^2`. Since i is
`√(-1)`, i cubed would be -i, and i squared would be -1. Our equation in now -i-2(-1). We can simplify -2(-1) and get 2. Our final equation is -i+2, or in standard form, 2-i.

Answer 2

Answer:
`\Large\boxed{Fourth~Choice.~f(x)=2-i}`

Concept:

Here, we need to know the power of imaginary numbers

i = √(-1)

i² = -1

i³ = -i

i⁴ = 1

Solve:

Given function expression

`f(x)=x^3-2x^2`

Given the requirement of the question

To find the expression for f(i)

Substitute values into the expression

`f(x)=(i)^3-2(i)^2`

Simplify the exponents

`f(x)=(-i)-2(-1)`

Expand the parenthesis

`f(x)=-i-(-2)`

`\Large\boxed{f(x)=2-i}`

Hope this helps!! :)

Please let me know if you have any questions