Question

S

Which point is a solution to the linear inequality y<-1/2x+2
(2,3)
(2,1)
(3,-2)
(-1,3)

Answer 1

(3, -2)

Explanation:

Put the coordinates of the points to the inequality and check:

y < -1/2x + 2

for (2, 3) → x = 2, y = 3

3 < -1/2(2) + 2

3 < -1 + 2

3 < 1 FALSE

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for (2, 1) → x = 2, y = 1

1 < -1/2(2) + 2

1 < -1 + 2

1 < 1 FALSE

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for (3, -2) → x = 3, y = -2

-2 < -1/2(3) + 2

-2 < -1.5 + 2

-2 < 0.5 TRUE

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for (-1, 3) → x = -1, y = 3

3 < -1/2(-1) + 2

3 < 1/2 + 2

3 < 2 1/2 FALSE