Question

The diagonals of a rhombus are 8 and 10 . the area of the rhombus is
20
40
80

Answer 1

40

Explanation:

In a rhombus the two diagonals intersect perpendicularly. So you can see a rhombus as the union of two triangles whose base is one of the diagonals of the rhombus and whose height is the half of the other diagonal.

Therfor you can calculate the area of the rhombus calculating the area of the two triangles that are the same.

In this case the area of each triangle must be
`(4* 10)/(2)= 20` (if you take the 10-lenght-side as the basis of the triangles).

Hence the area of the rhombus is 40 because is the double of the area of each triangle.

Answer 2

Area = 40

Explanation:

The area of a rhombus is

Area = a*b/2

Where a and b are the lengths of the diagonals.

Area = 8 * 10/2

Area = 40