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What is the enthalpy change for the following reaction:


C3H8(g) + 5O2 (g) --> 3CO2 (g) + 4H2O (l)


ΔHof C3H8 (g) = -103.8 kJ


ΔHof CO2 (g) = -393.5 kJ


ΔHof H20 (l) = -285.8 kJ

User Shaneika
by
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2 Answers

20 votes
20 votes

Step-by-step explanation:

(a) Collision claims tend to be skewed right because there are a few very large collision claims relative to the majority of claims.

These large collision claims skew the data to the right because they are outliers that draw the mean higher than it should be.

The answer cannot be "no large collision claims" or "many large collision claims" because then the data would not be skewed.

(b) Since there are two random samples comparing two means, we will be using a 2-Samp-T-Test. We will use Welch's approximate t-test, where we test the hypothesis that these two populations have the same mean.

We want to determine if 20-24 year old drivers have the same mean collision cost as 30-59 year old drivers.

(c) The null hypothesis is that the mean claim of collision costs for 20-24 year old drivers is the same as the mean claim of collision costs for 30-59 year old drivers.

We can also rewrite this as:

H₀: μ₁ = μ₂

where μ₁ is the mean collision claims for 20-24 year old drivers

and μ₂ is the mean collision claims for 30-59 year old drivers

The alternative hypothesis is that the mean claim of collision costs for 20-24 year old drivers is higher than the mean claim of collision costs for 30-59 year old drivers.

We can rewrite this as:

H₁: μ₁ > μ₂

Our variables have already been defined

(d) In order to calculate the p-value, we must find the test statistic first.

We can do so by using this formula:

\displaystyle t=\frac{x_1-x_2}{\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2} }}t=

n

1

s

1

2

+

n

2

s

2

2

x

1

−x

2

We are given these variables in the problem:

x_1=4590x

1

=4590

s_1=2302s

1

=2302

x_2=3670x

2

=3670

s_2=2029s

2

=2029

n_1=40n

1

=40

n_2=40n

2

=40

Substitute these variables into the formula for the test statistic.

\displaystyle t=\frac{4590-3670}{\sqrt{\frac{2302^2}{40} +\frac{2029^2}{40} } }t=

40

2302

2

+

40

2029

2

4590−3670

You can use the calculator to solve this expression, or plug the numbers into your calculator using: STAT - TESTS - 4:2-SAMPTTEST.

Your test statistic should be: t = 1.8962.

The calculator should also tell you the p-value; p = .0308.

(e) Since p = .0308 < α = .1, reject the null. We have convincing statistical evidence that the mean claim of collision costs for 20-24 year old drivers is higher than the mean claim of collision costs for 30-59 year old drivers.

User Katerina
by
2.9k points
21 votes
21 votes

Enthalpy of reaction

  • Enthalpy of products -Enthalpy of reactants
  • 4(∆H_2O)+3∆CO_2-∆C_3H_8
  • 4(-285.8)+3(-393.5)-(-103.8)
  • -1143.2-1180.5+103.8
  • -2220.7KJ

As ∆H is negative reaction is exothermic