Question

Question 1(Multiple Choice Worth 4 points)

(08.02 HC)

How many liters of 4.0 M NaOH solution will react with 0.30 liters 4.0 M H2SO4?

H2SO4 + NaOH → Na2SO4 + H2O

1.6 L
1.2 L
0.90 L
0.60 L

Answer 1

0.60 L.

Step-by-step explanation:

How many moles of
`\rm H_2SO_4`?

`n(\mathrm{H_2SO_4}) = c\cdot V = 4.0* 0.30 = \rm 1.2\; mol`.

How many moles of
`\rm NaOH` will react with all that 1.2 moles of
`\rm H_2SO_4`?

Balance the equation:

`\rm H_2SO_4 + 2\; NaOH \to Na_2SO_4 + 2\;H_2O`.

The coefficient in front of
`\rm H_2SO_4` is 1. The coefficient in front of
`\rm NaOH` is 2. Hence the ratio:

`\displaystyle \frac{n(\mathrm{NaOH})}{n(\mathrm{H_2SO_4})} = (2)/(1) = 2`.

Therefore

`\displaystyle n(\mathrm{NaOH}) = \frac{n(\mathrm{NaOH})}{n(\mathrm{H_2SO_4})} \cdot n(\mathrm{H_2SO_4}) = 2* 1.2 = \rm 2.4\;mol`.

What will be the volume of the
`\rm NaOH` solution?

`\displaystyle V(\mathrm{NaOH}) = (n)/(c) = (2.4)/(4.0) = \rm 0.60\;L`.