Question

ANSWER ASAP I NEED TO GRADUATE THIS WEEK

the coordinates (4, -1). What
17. A line has a point with the coordinates (-3,-2) and a point with the coord
is the slope of the line?
a. 1
-os
la mala
18. A line has a point with the coordinates (0,6) and a point with the coordi
the slope of this line?
with the coordinates (2,9). What is
Glow​

Answer 1

17.C

18.A

Explanation:

17. Slope=(y2-y1)/(x2-x1)

=(-1-(-2))/(4-(-3))

=1/7

18.Slope=(y2-y1)/(x2-x1)

=(9-6)/(2-0)

=3/2

Do you want 19 and 20 too?

Answer 2

Question 1:

For this case we have that by definition, the slope of a line is given by:

`m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}`

Where:

`(x_ {1}, y_(1)) and (x_ {2}, y_(2))`are two points through which the line passes.

`(x_ {1}, y_(1)) = (- 3, -2)\\(x_ {2}, y_(2)) = (4, -1)`

Substituting in the equation:

`m = \frac {-1 - (- 2)} {4 - (- 3)} = \frac {-1 + 2} {4 + 3} = \frac {1} {7}`

ANswer:

Option C

Question 2:

For this case we have that by definition, the slope of a line is given by:

`m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}`

Where:

`(x_ {1}, y_(1)) and (x_ {2}, y_(2))` are two points through which the line passes.

`(x_ {1}, y_(1)) = (0,6)\\(x_ {2}, y_(2)) = (2,9)`

Substituting in the equation:
`m = \frac {9-6} {2-0} = \frac {3} {2}`

ANswer:

Option A

Question 3:

For this case we have that by definition, the slope of a line is given by the following formula:

`m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}`

Where:

`(x_ {1}, y_(1)) and (x_ {2}, y_(2))`are two points through which the line passes.

We have as data:

`m = \frac {7} {8}\\(x_ {1}, y_(1)) = (- 2,1)`

Substituting in the formula:

`\frac {7} {8} = \frac {y_ {2} -1} {x_ {2} - (- 2)}\\\frac {7} {8} = \frac {y_ {2} -1} {x_ {2} +2}`

We substitute each of the points and see if the equality is met:

Point A: (6,8)

`\frac {7} {8} = \frac {8-1} {6 + 2}\\\frac {7} {8} = \frac {7} {8}`

Equality is met.

Answer:

Option A

Question 4:

For this case we have that by definition, the slope of a line is given by the following formula:

`m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}`

Where:

`(x_ {1}, y_(1)) and (x_ {2}, y_(2))`are two points through which the line passes.

We have as data:

`m = \frac {1} {6}\\(x_ {1}, y_(1)) = (0, -3)`

Substituting in the formula:

`\frac {1} {6} = \frac {y_ {2} - (- 3)} {x_ {2} -0}\\\frac {1} {6} = \frac {y_ {2} +3} {x_ {2} -0}`

We substitute each of the points and see if the equality is met:

Point A: (-3,0)

`\frac {1} {6} = \frac {0 + 3} {- 3-0}\\\frac {1} {6} = \frac {3} {- 3}`

It is not fulfilled!

Point B: (6, -2)

`\frac {1} {6} = \frac {-2 + 3} {6-0}\\\frac {1} {6} = \frac {1} {6}`

Equality is met!

ANswer:

Option B