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2 votes
Given the system of equations, match the following items.

2 x - y = 0
x + y = -3

[0 -1
-3 1]

[2 0
1 -3]

[2 -1
1 1]

Given the system of equations, match the following items. 2 x - y = 0 x + y = -3 [0 -1 -3 1] [2 0 1 -3] [2 -1 1 1]-example-1
User Squidbe
by
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2 Answers

6 votes

Explanation:

  • x+y=-3

x = -3 -y

  • 2x -y = 0

2(-3 -y) =0

-6 -2y = 0

-2y = 6

y = -3

  • x = -3 -y

= -3 -(-3)

= -3+3 = 0

2 votes

The x - determinant of the equation is
\left[\begin{array}{cc}0&-1\\-3&1\\\end{array}\right]

The y - determinant of the equation is
\left[\begin{array}{cc}2&0\\1&-3\\\end{array}\right]

The system determinant is
\left[\begin{array}{cc}2&-1\\1&1\\\end{array}\right]

How to find the determinants of x, y and the entire system?

The given system of equation include the following;

2x - y = 0

x + y = - 3

The x - determinant of the equation will be obtained by replacing coefficient of x with the constant terms.


\Delta x = \left[\begin{array}{cc}0&-1\\-3&1\\\end{array}\right]

The y - determinant of the equation will be obtained by replacing coefficient of y with the constant terms.


\Delta y = \left[\begin{array}{cc}2&0\\1&-3\\\end{array}\right]

The system determinant is obtained by removing the constant term and writing only the x and y coefficient in the matrix;


\Delta = \left[\begin{array}{cc}2&-1\\1&1\\\end{array}\right]

User AFG
by
6.1k points
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