Question

7. How much thermal energy is absorbed when 10.0 g of ice at 0.0 degrees C changes phase to liquid water at 0.0 degrees C? The molar mass, M, of water is 18.02 g/mol and the theoretical heat of fusion, Hfus, of water is 6.01 kJ/mol

Answer 1

3.34 kJ

Step-by-step explanation:

FIrst of all, we need to calculate the number of moles corresponding to 10.0g of ice. This is given by

`n=(m )/(M_m)`

where

`M_m = 18.02 g/mol` is the molar mas

m = 10.0 g is the mass

Substituting

`n=(m)/(M_m)=(10 g)/(18.02 g/mol)=0.555 mol`

Now we know that the heat of fusion is

`H_(fus)=6.01 kJ/mol`

so the thermal energy needed to fuse the ice is

`Q=n H_(fus) = (0.555 mol)(6.01 kJ/mol)=3.34 kJ`