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Write an equation in point-slope form of the line that passes though the given points. Then, write the equation in slope intercept form.

(-1,-2) and (2,4)

User Chengmin
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1 Answer

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Answer:

Please check the explanation.

Explanation:

Given the points

  • (-1, -2)
  • (2, 4)

Finding the slope between (-1, -2) and (2, 4)


\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)


\left(x_1,\:y_1\right)=\left(-1,\:-2\right),\:\left(x_2,\:y_2\right)=\left(2,\:4\right)


m=(4-\left(-2\right))/(2-\left(-1\right))


m=2

Using the point-slope form


y-y_1=m\left(x-x_1\right)

where m is the slope of the line and (x₁, y₁) is the point

substituting the values m = 2 and the point (-1, -2)


y-y_1=m\left(x-x_1\right)


y -(-2) = 2(x-(-1)

Thus, the point-slope form of the line equation is


y -(-2) = 2(x-(-1)

now, write the slope-intercept form of the line equation y = mx+b


y-\left(-2\right)=2\left(x-\left(-1\right)\right)


y+2=2\left(x+1\right)

subtract 2 from both sides


y+2-2=2\left(x+1\right)-2

Simplify


y=2x+0


y = 2x

Therefore, the equation in slope-intercept form is:


  • y = 2x
User Jwaliszko
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