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A 100-kg moving at 15 m/s collides with a 50-kg cart at rest causing both cars to move together in the same direction. If momentum is conserved, at what speed are the two carts now moving?

User Elenst
by
6.0k points

2 Answers

3 votes

Answer:

30m/s

Step-by-step explanation:

100 / 50 = 2 * 15 = 30m/s

User Tony Wang
by
5.9k points
1 vote

Answer:


\boxed{\text{10 m/s}}

Step-by-step explanation:

Data:

Cart 1: m₁ = 100 kg; v =15 m/s

Cart 2: m₂ = 50 kg; v₂ = ?

Calculations:

I assume that the two carts are going at the same speed v₂ after the collision.


\begin{array}{rcl}\text{Momentum before collision} & = & \text{Momentum after collision} \\\text{100 kg} *\text{15 m/s} & = &\text{100 kg} * v_(2) + \text{50 kg} * v_(2)\\\text{1500 m/s} & = & 100 v_(2) +50 v_(2)\\\text{1500 m/s} & = & 150 v_(2)\\v_(2)& =&\textbf{10 m/s}\\\end{array}\\\\\text{The two carts are now moving at a speed of }\boxed{\textbf{10 m/s}}

User Sprugman
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6.0k points