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Given: circle k(O), m

LM
= 164°
m
WK
= 68°, m∠MLK = 65°
Find: m∠LMW

Given: circle k(O), m LM = 164° m WK = 68°, m∠MLK = 65° Find: m∠LMW-example-1
User Jay Prall
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1 Answer

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Let P be a point outside the circle such that triangle LMP has legs coincident with chords MW and LK (i.e. M, W, and P are colinear, and L, K, and P are colinear). By the intersecting secants theorem,


m\angle LPM=\frac{m\widehat{LM}-m\widehat{WK}}2\impliesm\angle LPM=48^\circ

The angles in any triangle add to 180 degrees in measure, and
\angle MLK\congruent\angle MLP and
m\angle LMW=m\angle LMP, so that


m\angle MLK+m\angle LPM+m\angle LMP=180^\circ


\implies\boxed{m\angle LMW=67^\circ}

User Erik Thysell
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