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What are the zeros of the function? f(x)=3x^2−24x+36 Enter your answers in the boxes. The zeros of f(x) are and

User Rohith R
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1 Answer

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</p><p>f(x)=3x^2-24x+36 \\</p><p>0=3(x-2)(x-6) \\</p><p>0=(x-2)(x-6)</p><p>

There will be 2 solutions.


</p><p>x-2=0\Longrightarrow\boxed{x_1=2} \\</p><p>x-6=0\Longrightarrow\boxed{x_2=6}</p><p>

Hope this helps.

r3t40

User Mizuki
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