Question

The deer population in a region is expected to decline 1.1% from 2010-2020. Assuming this continued how many deer would there be in the region in the year 2060 if the 2010 population was 1,578?

1,406

1,510

1,493

1,385

Answer 1

The population would be 1,493.

Explanation:

Given,

The initial population, P = 1,578, ( In 2010 )

Also, the decline rate per 10 years, r = 1.1 %,

And, the number of the periods of 10 years since, 2010 to 2060, n = 5,

Hence, the population in 2060 would be,

`A=P(1-(r)/(100))^n`

`=1578(1-(1.1)/(100))^5`

`=1493.09849208\approx 1493`

Option third is correct.

Answer 2

Option C. 1,493

Explanation:

If the deer population in a region is expected to decline 1.1% from 2010 to 2020. Assuming this continued, we can say that the deer population decreases 1.1% each ten years.

From 2010 to 2060 there are 50 years. If the deer population decreases 1.1% each ten years, then it will decrease 5.5% in 50 years.

If the population in 2010 was 1,578. Then, the population in 2060 is going to be:

Using the rule of three:

If 1578 ----------------> Represents 100%

X <----------------- 5.5%

X = (5.5%x1578)/100% = 86.79 ≈ 87

Then the total population in 2060 is: 1578 - 87 = 1491

None of the answers equal to 1491. That's why I assume the correct answer must be Option C. 1,493. Given that it's the closest answer!