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Please respond asap!!!

Please respond asap!!!-example-1
User ZeroKelvin
by
8.2k points

2 Answers

2 votes

Answer:

Difference = 20.47 square units

Explanation:

Points to remember

Area of circle = πr²

Where r - Radius of circle

Area of triangle = bh/2

Where b - Base and h- Height

It is given a circle with radius 3 units

And a right angled triangle with angles 30, 60 and 90 and hypotenuse = 6 units

To find the area of circle

Here r = 3 units

Area = πr²

= 3.14 * 3 * 3

= 28.26 square units

To find the area of triangle

Here sides are in the ratio Base : Height : hypotenuse = 1 : √3 : 2

= Base : Height : 6

= 3 : 3√3 : 6

Base b = 3 and height h = 3√3

Area = bh/2

= (3 * 3√3)/2

= 7.79 square units

To find the difference

Difference = 28.26 - 7.79

= 20.47 square units

User Madao
by
8.0k points
2 votes

ANSWER


9(\pi - ( √(3) )/(2) )

Approximately, A=20

EXPLANATION

The circle has radius r=3 units.

The height of the triangle is ,


h = 6 \cos(60 \degree) = 3

The base of the triangle is


b = 6 \sin(60 \degree) = 3 √(3)

The area of the triangle is


(1)/(2) bh


= (1)/(2) * 3 √(3) * 3


= (9)/(2) √(3)

The area of the circle is


\pi {r}^(2)


= {3}^(2) \pi


= 9\pi

The difference between the area of the circle and the triangle is


9\pi - (9)/(2) √(3) = 9(\pi - ( √(3) )/(2) )

User Zibri
by
7.2k points