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What is the value of -6x3-y2-3xy if x=-2 and y=4

2 Answers

3 votes

Answer:

The value of given expression = 56

Explanation:

It is given an expression in variable x and y

-6x³ - y² - 3xy

To find the value of given expression

Let expression be,

-6x³ - y² - 3xy

When x = -2 and y =4

-6x³ - y² - 3xy = -6(-2)³ - 4² - (3 * -2 * 4)

= -6*-8 - 16 + 24

= 48 - 16 + 24

= 56

Therefore the value of given expression is 56

User Binco
by
6.8k points
6 votes

Hello!

The answer is:

The value of the given expression evaluated with x equals to -2 and y equals to 4, is equal to 56 units.

Why?

To solve the problem, we need to evaluate both variables for the given values:


x=-2

and


y=4

So, we are given the expression:


-6x^(3)-y^(2)-3xy

Then, evaluating the given values for both variables, we have:


-6*(-2)^(3)-(4)^(2)-3*(-2)*(4)=(-6*-8)-(16)+24=48-16+24=56

Hence, we have that the answer is:

The value of the given expression evaluated with x equals to -2 and y equals to 4, is equal to 56 units.

Have a nice day!

User Pavunkumar
by
6.3k points
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