Question

Solve the following system of equations:
-8x+3y=7
13-3y=-17

X=?
Y=?

Answer 1

For this case we must solve the following system of equations:

`-8x + 3y = 7\\13x-3y = -17`

If we add both equations we have:

`-8x + 13x + 3y-3y = 7-17\\5x = -10\\x = \frac {-10} {5}\\x = -2`

We find the value of the variable "y":

`3y = 7 + 8x\\y = \frac {7 + 8x} {3}\\y = \frac {7 + 8 (-2)} {3}\\y = \frac {7-16} {3}\\y = \frac {-9} {3}\\y = -3`

Thus, the solution of the system is (-2, -3)

ANswer:

(-2, -3)

Answer 2

x = -2 and y = -3

Explanation:

It is given that,

-8x + 3y =7 ----(1)

13x - 3y =-17 -----(2)

To find the value of x and y

eq(1) + eq(2) ⇒

-8x + 3y = 7 ----(1)

13x - 3y = -17 -----(2)

5x + = -10

x = -10/5 = -2

Substitute value of x in eq (1)

-8x + 3y =7 ----(1)

-8 * -2 + 3y = 7

16 + 3y = 7

3y = 7 - 16 = -9

y = -9/3 = -3

Therefore x = -2 and y = -3