Question

Calculate the number of moles of chlorine gas needed to form 14 moles of iron (iii) chloride

Answer 1

`\boxed{ \text{21 mol}}`

Step-by-step explanation:

(a) Balanced equation

You haven't given the complete reaction, but we can use a partial equation so long as Cl is balanced.

3Cl₂ + … ⟶ 2FeCl₃ + …

(b). Calculation

You want to convert moles of FeCl₃ to moles of Cl₂

The molar ratio is 3 mol Cl₂:2 mol FeCl₃

`\text{Moles of Cl$_(2)$} =\text{14 mol FeCl$_(3)$} * \frac{\text{3 mol Cl$_(2)$}}{\text{2 mol FeCl$_(3)$}} = \text{21 mol Cl$_(2)$}\\\\\text{You need }\boxed{ \textbf{21 mol of Cl$_(2)$}}\text{ to form 14 mol of FeCl$_(3)$}.`