Question

How many milliliters of a 1.25 molar hydrochloric acid (HCl) solution would be needed to react completely with 60.0 grams of calcium metal? (2 points)

Ca (s) + 2HCl (aq)yields CaCl2 (aq) + H2 (g)

Answer 1

2400 mL

Step-by-step explanation:

`Ca + 2HCl \implies CaCl_2 + H_2`

According to this equation, the stoichiometric ratio between
`Ca` and
`HCl` for the complete reaction is 1:2.

We know that the number of moles of
`Ca` can be calculated using the mole formula. (number of moles = mass / molar mass)

Moles of Calcium =
`(60)/(40)` = 1.5 mol

So the moles of
`HCl` =
`1.5 * 2` = 3.0 mol

Volume of HCl solution = Moles of HCl/ concentration of HCl

Volume of HCl solution =
`(3)/(1.25)` = 2400 mL