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How many milliliters of a 1.25 molar hydrochloric acid (HCl) solution would be needed to react completely with 60.0 grams of calcium metal? (2 points)

Ca (s) + 2HCl (aq)yields CaCl2 (aq) + H2 (g)

User Can Gencer
by
6.5k points

1 Answer

6 votes

Answer:

2400 mL

Step-by-step explanation:


Ca + 2HCl \implies CaCl_2 + H_2

According to this equation, the stoichiometric ratio between
Ca and
HCl for the complete reaction is 1:2.

We know that the number of moles of
Ca can be calculated using the mole formula. (number of moles = mass / molar mass)

Moles of Calcium =
(60)/(40) = 1.5 mol

So the moles of
HCl
=
1.5 * 2 = 3.0 mol

Volume of HCl solution = Moles of HCl/ concentration of HCl

Volume of HCl solution =
(3)/(1.25) = 2400 mL

User Paul Rouget
by
6.9k points