Question

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ESPOO
1. A cylindrical swimming pool has a diameter 32 of feet and a height of 7 feet. About how many gallons of
water can the pool contain? Round your answer to the nearest whole number. (1 ft - 7.5 gal​

Answer 1

42,223 gallons

Explanation:

Find the volume of the pool and then multiply that by the conversion factor 1 ft³: 7.5 gallons.

If the pool diameter is 32 feet, then the pool radius is 16 feet.

The volume here is V = πr²h, or V = π(16 ft)²(7 ft) = 5629.73 ft³

Multiplying this volume by 1 ft³: 7.5 gallons, we get:

(5630 ft³)(7.5 gallons / 1 ft³) = 42,223 gallons